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Valentin Fadeev

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Edited by Valentin Fadeev, Sunday, 16 Jan 2011, 23:18

With the new courses yet to start, hopefully providing fresh material for new posts, I have been spending time going through some excercises from new textbooks.

As integrals have always been my favourite part of calculus, I decided to take down this solution, because it just looks nice. It also illustrates the principle: don't make a substitution, until it becomes obvious.

MathJax failure: TeX parse error: Extra close brace or missing open brace

equation sequence two times x cubed minus three times x squared plus one equals two times x cubed minus two times x squared minus x squared plus one equals two times x squared times open x minus one close minus open x minus one close times open x plus one close equals open x minus one close times open two times x squared minus x minus one close equals open x minus one close times open x squared minus x plus x squared minus one close equals open x minus one close times open x times open x minus one close plus open x minus one close times open x plus one close close equals open x minus one close times open x minus one close times open two times x plus one close equals left parenthesis x minus one times right parenthesis squared times open two times x plus one close

cap i equals Square root of three times integral over negative one divided by two under zero d times x divided by Square root of left parenthesis x minus one times right parenthesis squared times open two times x plus one close

Since negative one divided by two less than or equals x less than or equals zero we have negative three divided by two less than or equals x minus one less than or equals negative one and zero less than or equals two times x plus one less than or equals one , so we need to choose negative sign when taking square root of the quadratic term.

equation sequence cap i equals Square root of three times integral over negative one divided by two under zero d times x divided by Square root of two times x plus one times open one minus x close equals Square root of three times integral over negative one divided by two under zero d of Square root of two times x plus one divided by one minus x

It's now that the substitute equation left hand side two times x plus one equals right hand side t squared becomes an obvious choice.

equation sequence cap i equals Square root of three times integral over zero under one d times t divided by one minus t squared minus one divided by two equals Square root of three times integral over zero under one d times t divided by three divided by two minus t squared divided by two equals two divided by Square root of three times integral over zero under one d times t divided by one minus t squared divided by three equals two times integral over zero under one d of t divided by Square root of three divided by one postfix minus left parenthesis t divided by Square root of three times right parenthesis squared equals two times hyperbolic tangent super negative one of t divided by Square root of three vertical line sub zero super one equals two times hyperbolic tangent super negative one of one divided by Square root of three

 

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neil

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OBVIUOS??
Valentin Fadeev

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well, it's quite depressing when a textbook solution suggests a substitution "out of the blue". however, in fact the problem may often be cast into a form when change of variable is just "wrapping" of a frequently occurring expression and giving it a placeholder name. That's what I'm trying to achieve throughout my studies. Almost all "special functions" were introduced in a similar fashion.

On a broader scale I assume that different wrappings may lead to different pictures of the world...