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The neighbouring numbers are opposite corners. 

And 1-4 and 5-8 are opposite too.

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Total of corners for each and every face = 18

Jan

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Pairs of opposite edges?

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That's what I said. Is that it?

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Pairs of opposite edges like 14 and 35 have the same sum, not sure if that is to say?

If we join up each of the even numbers to all the others, so we have six joining lines, what do they form the ages of?

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From very different perspective,

Let point 5 be (-1,-1,-1), point 2 be (+1,-1,-1), point 7 be (+1,+1,-1), point 4 be (-1,+1,-1),

point 8 be (-1,-1,+1), point 3 be (+1,-1,+1), point 6 be (+1,+1,+1), point 1 be (-1,+1,+1)

and,

N5=(1-x)(1-y)(1-z)/8, N2=(1+x)(1-y)(1-z)/8, N7=(1+x)(1+y)(1-z)/8, N7=(1-x)(1+y)(1-z)/8,

N8=(1-x)(1-y)(1+z)/8, N3=(1+x)(1-y)(1+z)/8, N6=(1+x)(1+y)(1+z)/8, N1=(1-x)(1+y)(1+z)/8

where, -1<=x<=1, -1<=y<=1, -1<=z<=1

So, if the temperatures of these points are t5,t2,t7,t4,t8,t3,t6,t1,

the temperature at (x,y,z) is

t=N5*t5+N2*t2+N7*t7+N4*t4+N8*t8+N3*t3+N6*t6+N1*t1

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Joining evens forms a tetrahedron.

Joining odds forms another tetrahedron.

Jan

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Hi, Richard, Jan, everyone.

My idea may be too far from this discussion, very sorry.

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Nothing is too far, we have a structure with features that we can see in an elementary way but also may have some deeper maths underlying them.

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Thanks, Richard.