
I've had these olive trees exactly two years and this year they have fruited quite well, as you can see. When I first bought them, I posted here about them and about what may be the world's oldest olive tree.

I've had these olive trees exactly two years and this year they have fruited quite well, as you can see. When I first bought them, I posted here about them and about what may be the world's oldest olive tree.
You may not have met this remarkable palindromic number before.
is a prime. Because it contains , the Number of the Beast, this prime is nicknamed Belphegor's prime, after one of the Seven Princes of Hell. Here he is
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This prime was discovered by Harvey Dubner, an expert in finding large unusual primes, and is one of a sequence which you can find on the Online Encyclopedia of Integer Sequences (OEIS) here. The next is
The OEIS seems to suggest this is only a 'probable' prime. A probable prime is a number that has passed a long series of tests from which we can conclude the probability it is not prime is very small. We also have exact tests but they are much slower, because they involve much longer calculations. In this case I found that according to SageMathCell, which I think uses an exact test, this is a definite prime, not just a probable one.
The next number after that would be a probable prime with more than ten times as many digits, so I won't try to display it here or prove it is a definite prime.
How did Dubner discover Belphegor's prime? Purely guessing but maybe he spotted the is prime and thought that was neat, so he then tried inserting more zeros and putting the numbers so formed to a probabilistic primality test until he struck gold with thirteen zeros each side of the evil .
I haven't really investigated but I thought interesting palindromic primes might not be all that rare. If there are seven demons in hell, what if we change to in recognition of the fact. Is
prime? Can we prove it? YES WE CAN! How spooky is that?
I hereby name it the Seven Demons Prime.
Picture credit http://en.wikipedia.org/wiki/File:Belphegor.gif, public domain.
My brother photographed one last week It's a crane, Grus grus.

Not a great photo but good enough to see clearly that it's a crane. It's thought these imposing birds were once common in Britain but they were hunted for their feathers and to put on the tables of the upper classes. According to Gurney (quoted in [1]) in 1251 Henry III held a Christmas feast at York at which 115 cranes were eaten (amongst other things presumably).
So from overhunting they became rarer and rarer and 1542 was the last time the birds were reconded as breeding in England.
Until 1979, when a couple of young cranes flew in. There had been occasion migrants in the intervening period but no breeding pairs — but these two did.
So some birds flew here of their own accords and there has now been some reintroduction, and no there are an estimated 250 birds in the UK. In 2025 there were 87 pairs documented and 37 chicks were raised.
So a comeback, but it's still a very rare bird in the UK and my brother was lucky to spot this one.
[1] Andrew Stanbury and the UK Crane Working Group, The changing status of the Common Crane in the UK.
The Pigeonhole Principle says, of course, that if there are more pigeons than pigeonholes then we must be able to find a pigeonhole with more than one occupant.
The Cut The Problem ask for a proof (using the Pigeonhole Principle) that there is a power of whose last three digits are , which sounds quite surprising.
But let's imagine we have pigeonholes numbered . Calculate distinct power of , divide each by and find the remainder, then put that power in the pigeonhole with the same number as the remainder.
There is one more 'pigeons' than pigeonholes, so there must be a pigeonhole with two occupants, that it, two powers that leave the same remainder on division by .
Suppose these are and , being the smaller. Because they leave the same remainder when divided by , must be a multiple of .
can't divide a power of , so it must divide . This means when worked out ends in three zeros , which in turn means ends in .
We can run a computer search quite easily and we find that in fact
fits the bill.
This result can be generalised of course and we can prove that for example there must a power of that ends in a trillion zeros followed by , although given that even the zeros would take up nearly GB the browser is too small to display it.

12th September 2026
I expect you know the word kibosh; putting the kibosh on something means it has been brought to a sudden stop or been thwarted etc.
I've never thought about its origins until today but tacitly assumed it was from Yiddish — it looks a bit like kibitzer, an onlooker who proffers unwanted advice, which the OED says cautiously is 'perhaps modelled on a Yiddish lexical item'.
The trouble is, it turns out, no-one has found a Yiddish word that kibosh could be derived from, making the Yiddish origin theory unlikely. But plenty of other ideas have been proposed.
From the OED
Wordorigins.org mentions (but doesn't seem convinced by) another possibility
Michael Quinion
OUPBlog
In a 2013 post 'Three recent theories of “kibosh”' we find further candidates.
Wiktionary
I guess this list is not exhaustive but what stands out is we don't really know where the word came from. It might be from none of them or it might have come from two or more being confused and ending up merged into one. Or someone might just have coined it with humorous intentions and it caught on. This happened with e.g. discombobulate.
Can there be four square numbers in arithmetic progression? Can four numbers that are perfect powers be in arithmetic progression?
The simple answers are no and yes!
First I'll sketch the history of the first question, which developed from a problem studies by Islamic mathematicians more than a thousand years ago.
Then I'll outline how we know the answer to the second question and give an a examplle.
A little background: An arithmetic progression (AP) is when a series of numbers go up (or down) in equal steps, and this size of this step is called the common difference. For example 1, 4, 7, 10 are four numbers in AP, with common difference 3.
The congruum problem asks for triplets of square numbers that are in arithmetic progression, for example 1, 25, 49, whose common difference 24 is called the congruum.
Finding congruums (or congrua)? attracted the interest of medieval and later mathematicians, with several mathematical superstars getting in on the act.
According to Wikipedia the problem was first investigated in the 10th century, by Abu Jafar al-Khazin, who gave example such as the one above and found a general solution.
Things really hotted up in 1225 though, because the Holy Roman Emperor at that time organised a mathematical tournament. Can you imagine such a thing nowadays?
The prize was carried off by one Leonardo of Pisa, better known as Fibonacci, who wrote about the eponymous series 1, 1, 2, 3, 5, 8, ..., and about the Indo-Arabic numerals which replaced Roman numerals and to become the system used today.
Next on the stage is Fermat, lawyer and amateur mathematician who made a claim that got called Fermat's Last Theorem even though it wasn't really a theorem because at the time he never actually proved it (as far as we know). He also made a conjecture about squares in AP — that it is impossible to find a congruum that works for four squares, not just three. Could there be numbers that were in AP?
This challenge was taken up by Euler, another giant famous for many things, including introducing the symbol for the base of natural logarithm. He published a proof but by that time he had low vision and had a helper to tale his dictation, so some writers are not sure the published version is accurate.
Since that time there have been many proofs published but in the literature there are also authors who have commented flaws in earlier papers, and there is active research right up to the present day.
Now for the second problem. Can four numbers that are perfect powers be in arithmetic progression?
Absolutely. Start with if you like. The common difference is , so the next term would be . But, you will say, is not a perfect power. No, but is. So scale everything up by .
Now we get the four terms
We can use Python as a sort of super-calculator
1*73**2, 25*73**2, 49*73**2, 73**3
(5329, 133225, 261121, 389017)
133225 - 5329, 261121 - 133225,389017 - 261121
(127896, 127896, 127896)
and sure enough we have our AP.
Surprisingly we could in principle carry this as far as we like and get a million or a gazillion perfect powers in AP, although as you see the numbers grow dizzyingly fast; we have gone from 24 to 127896 in one step. So I imagine we would soon run out of resources and get to numbers too big to actually write dowm!
I hadn't thought about this until reading something last night with parallel texts in English and German and noticed the German equivalent was KI. Interesting, I thought.
It's short for Künstliche Intelligenz, which is what's called a calque, when individual parts of a compound word are translated literally into the host language.
For example German Regenwald became English rainforest, from Regen, 'rain' and Wald, 'forest'.
Exploring what 'artificial intelligence' translates to in a few other languages, with Gemini doing the heavy lifting, all those I looked into calqued the English phrase, but the abbreviations are overwhelming 'AI', whatever the actual word in a language. For example in Chinese (according to Gemini) artificial intelligence translates as 人工智能 but you could informally write 这个 AI 工具很好用, 'This AI tool is very useful'.
The only exception I found were the Romance languages, which generally put the adjective after the noun, so logically enough we have e.g Spanish inteligencia artificial, IA; Dutch (sometimes) and some Scandinavian languages use KI, like German — but not Swedish where artificial intelligence is artificiell intelligens, AI, more or less the same English).
This definition for the Oxford English Dictionary made me smile, 'View entry' seemed very apt.

The word door goes back to early Proto-Indo-European, perhaps as far back as we can trace that reconstructed language. It hasn't changed much in all that time; the original root would have been something like *dwer- and words derived from it appear in nearly all branches of the PIE family, with senses of 'door' or 'gate' or 'outdoors'.
The Italic branch has given us several familiar words: Latin foris, 'door' gave forum, because forums are outside, and because forums are a good place for discussing legal matters we got forensis, which ends up as English forensic. We also have foreign, someone or something from outside, which reached us via Anglo-Norman.
I'll finish appropriately with a Deoch An' Doris, Scots Gaelic 'A Drink for the Door', the same idea as 'One for the Road'. Cheers!
This is a solution to the problem "A Quick Puzzle — Find x" posted 1/9/26.

Comment Trisecting an angle with straightedge and compasses was a problem posed in antiquity and which many mathematicians attempted to solve over the ages, until Wantzel proved it was impossible in 1837.
So have we achieved the impossible? Well, no. The original problem assumed the use of an unmarked straight edge, and our construction requires one we can mark. Or we could use three rods of equal length.
Our construction formed the basis of an angle trisection method given by Étienne Pascal, father of Blaise, he of the triangle which you will recognise
1 1
1 2 1
1 3 3 1
1 4 6 4 1
However what was essentially the same method was already known to Archimedes over a millennium earlier.
There is an old joke allegedly from a real exam script

I'm not talking about some kind of Creature from the Swamps but about a recent (2026) discovery that the tiny water droplets in fog are home to populations of bacteria [1].
The bacteria grow and divide in the water droplets, so it looks as though they like it there, and amazingly they can eat formaldehyde and break it down into carbon dioxide and water; in fact it appears they break down more than they can eat and it's thought that this is because too much of it would harm them. Formaldehyde is harmful to human health [2] and the waterborne bacterial may play a useful part in purifying the air.
That's what made me think about formaldehyde as a domestic pollutant. Friends have Dyson air purifiers and removing formaldehyde is an important part of what these devices do.
So maybe the bacteria in water droplets have an important role in cleansing air. And I wonder if they exist in clouds, which are just fog high up. It may be hard to find out; the researchers had difficulty getting the fog samples they wanted because wind disturbs the fog and getting good samples from clouds thousands of feet up where winds are much stronger would be difficult.
I have to thank science YouTuber Anton Petrov for his video which put me on to this research.
In the Phys.Org article I read, one of the researchers was quoted at the end as cracking a joke, so I'll end with (a rather appropriate) joke too.
I tried to catch some fog. But I missed.
[1] https://phys.org/news/2026-05-fog-alive-droplets-host-bacteria.html#google_vignette
My brother snapped these Mares' Tails, high altitude (20,000 feet and counting) ice crystal clouds. Their meteorological name is Cirrus uncinus, which apparently means 'curly hooks'.

It's interesting that different kinds of cloud have double-barrelled 'binomial' names with a genus and a species, a form generally kept for living things. But (thanks Gemini!) I found that viruses have binomial names too, although whether viruses are alive is debatable.
Karl Linnaeus, whose influence is pne of the main reasons binomial names are used in biology. even explored a similar naming scheme for minerals, considered by him a third 'kingdom' (and we still speak of 'Animal, Vegetable and Mineral') but ultimately it was not adopted by the scientific world.
Clouds are an exception amongst non-animate entities: Luke Howard who at the beginning of the 19th century famously pioneered assigning systematic names to cloud forms imitated Linnaeus in using binomial names and his scheme has survived.

EC = CD = DF as shown. Find x.

Isn't that neat? It was posted on Quora by Alexander Ferrugia, along with a proof that the pattern goes on forever. His proof was quite long though, and I found one which is a bit shorter.
Something that jumped out at me was the resemblance to recurring decimals. , and and I thought there had to be a connection. So I took the second line (the first doesn't fully show what the pattern is, because 6 doesn't appear) and played with it in the Python Shell, trying to get 16, 50 and 33, the numbers on the left hand side ...
100/6, 100/2, 100/3
(16.666666666666668, 50.0, 33.333333333333336)
Of course that's not right, we only want the whole number part. So let's subtract the fractional parts...
100/6 - 2/3, 100/2, 100/3 - 1/3
(16.0, 50.0, 33.0)
... and now it works. What about the right hand side? If we break it up we see it represents .
To get the equivalent expressions for the -th line we can just replace by everywhere and now we get
, with the left-hand side becoming
We want to prove these two expressions are equal and we can do that very easily. First make them more general by replacing by , giving
and
It is not hard to see that if these were expanded we would obtain cubic polynomials of the form . How can we prove they are the same? We might use paper and pencil to expand them and collect terms in the good old fashioned way. Or we could enter them into reliable computer algebra system and let it do the heavy lifting.
Or much more elegantly we can use this fact
| If two cubic polynomials of the form take identical values for four different values of they are equal. |
Why is this true? Because four values let us set up four equations and solve them to find the four constants .
But we have the requisite four values! This post began with them and so we have proved the two expressions are equal for any value of and for any value of in particular.
Many or most do (have unusual names), you see. A handful are perfectly explicable, such blackberry and blueberry from their colour, and Loganberry because in 1881 James Logan accidentally crossed a blackberry with a raspberry.
But many are inexplicable. What has a gooseberry have to do with geese or a strawberry with straw? A word story commonly advanced for gooseberry is that the first bit is a borrowing from French grosele or Dutch croesel. both ultimately from a Germanic root meaning 'crisp' or 'curly'. But the OED is unconvinced, and why would a gooseberry be described as curly?
As for strawberry, it was already in Old English as streawberigei, but where the straw comes into the mix is uncertain.
But at least these two fruits start with a recognisable element having a meaning in its own right., even if it is hard to link with the fruit concerned. Many names of the form 'something-berry' start with a element that is not a word on its own, isn't found anywhere else in the language and on its own has no meaning for native speakers.
The classic example is cranberry. Whatever is a cran? ¶ What does it mean? Well in this case we think we have an etymology: it was originally a crane-berry, as in the bird, but the 'e' got dropped and the meaning forgotten. (But why it was called a craneberry is still a mystery).
This cran is an example of a unique morpheme. A morpheme is like a sort of atom of language, the smallest unit of language and indivisible, and all words are made up from one or more morphemes. A morpheme may or may not be able to stand on its own. For example bookmark has two morphemes that can be independent words. whereas the un- in unhappy cannot exist alone. But crucially, it carries meaning; the cran in cranberry no longer does and contemporary speakers cannot explain what it means.
And most of the X-berry clan are like this; the X- may have a recognised etymology or it may be uncertain, but either way the X is a unique morpheme, found only in this combination, and whatever meaning it may once have had has evaporated.
Of course there are other examples of unique morphemes that have nothing to do with fruit; often quoted example are luke- in lukewarm, -ept in inept and twi- in twilight. The are often called 'cranberry morphemes' in fact, because that was the example used in early writings about this linguistic oddity. But they are particularly common in the vocabulary of berries.
For more example. think of huckle- (what's a huckle) and mul- and bil- and rasp-, all mysterious. Whortleberry looks at first as though it is not a unique morpheme, because whortle is a distinct word. but alas when we look it up we discover it is simply short for whortleberry, so it hardly counts. And then there is lingon-, borrowed from a Swedish word meaning something like 'heather berry' in Swedish, but now a unique morpheme in English.
Why are these unique morphemes there if they don't mean anything? Well we need them, they have a purpose which is to distinguish between different kinds of berry. So they do not need to carry meaning, they only need to be A. different, and B. easy enough for speakers to remember them.
¶ Scrabble players and word geeks may point out that a cran is a measure of herrings, but that is a different word, not our cran.
Picture credit Wikimedia, public domain
Imagine 5 unsociable people live on the surface of a tiny spherical world. Being unsociable they want to arrange themselves so the smallest distance between any two them is as big as possible. How can they do this?
If there were 6 of them they could position themselves at the vertices of a regular octahedron, as in this model [1] of a Sulphur Hexafluoride molecule, where 6 Fluorine atoms surround a single Sulphur atom. Electrostatic repulsion causes the Fluorine atoms to take up this octagonal configuration.
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We can measure the distance between two points that lie on a sphere by giving the angle they make at the centre and you can see that in this case all the angles are 90°.
But now suppose one of them jumps in a spaceship and flies off the some other tiny world. Now the remaining 5 have a little more space to spread themselves out more.
Except they don't! 5 points can't do any better than 6 could and the best minimum distance that can be achieved is still 90°. Here's my attempt at a proof.
Here I showed that
If there are five points on the surface of a sphere, then no matter how they are arranged at least 4 of them lie in the same hemisphere.
I think this result may have first been published by Martin Gardner, although I don't have the reference.
You can think of this as being like the Northern hemisphere, including the Equator and the North Pole, and 2 or more points must lie on the Equator.
If all 4 points lie on the Equator the greatest possible spacing is 90°, achieved when they are situated at the corners of a square inscribed in the Equator.
Otherwise we must have at least 2 on the Equator and at least 1 in the same hemisphere but not on the Equator. The greatest possible separation between this point and the 2 on the Equator is 90°, achieved when that point lies at the North Pole. So, either way, there must be a pair of points separated by 90° or less.
We'd like the configuration to be as symmetrical as possible, so we can put 3 points at the vertices of an equilateral triangle inscribed in the Equator and the other 2 at the North and South Poles.
At this point you might wonder if there are molecules with 5 Fluorine atoms surrounding a single atom of some other element, and if so are the Fluorines in the arrangement described above. The answers are Yes and Yes. Here's a picture of a Phosphorus Pentafluoride molecule [2]
![]()
This problem of optimally spacing points on a sphere, which has always fascinated me, is known as the Tammes problem and the best configuration for 2-14 points and 24 points were found and proved between 1943 and 2015 [3]. It is a hard problem, in that it has to be solved for each number individually. I imagine we can find estimates for the general case but finding exact solutions is challenging.
[1] Wikimedia Commons public domain.
[2] Wikimedia Commons public domain.
[3] Wikipedia Tammes problem.
Here's a Sun Dog I snapped one evening last week.

Sun Dogs are seen when the sun's light is refracted by flat hexagon ice crystals drifting in the clouds.

In favourable conditions, if the cloud formation is right and no nearby objects get in the way, we may see a pair of Sun Dogs, 22° left and right of the sun, but this is rarer than seeing just the one.
They fall into the class of phenomena you don't notice until something or someone makes you aware and then you realise they are quite common and see them frequently. Sun Dogs are more often visible than rainbows and I spot them often, usually looking West as the sun is setting in a bank of thin high cirrus clouds. You can see them to the East at sunrise too, of course, it's just that I see sunset more often.
These Sun Dogs are just a small part of a whole complex of arcs and circles that have sometimes been observed, although unless we are in the mountains or in Antarctica we are unlikely to witness them. My sketch below only includes the best known halo-related phenomena; at least 119 have been documented.

I suppose this must have been solved thousands of times but I wanted to find my own solution,.
I tried with a few 4-digit numbers at first to see if I could get any intuition but without success. I did think of writing a program to do a brute force search for a solution but that felt like cheating. Knowing what I know now it's a good thing I gave up the idea, as you'll see.
After a lot of thinking I came up with this.
Suppose the number is , where is the last digit and the value represented by the remaining digits. For example if the number was 2026 we would have and . Suppose our number has digits.
Then after has been moved to the front its place value will be . The remaining digits will have shifted one place right, so now represent . For example if we apply the process to 2026 we get .
Since the new number is double the original one we can write
which gives . This means the left-hand side must be divisible by 19 and since is a single digit it cannot be a multiple of 19, so must be.
It's not hard to find a suitable value of by hand but I was lazy and wrote a short Python program to do the heavy lifting.
d = 1
while not (10**d - 20) % 19 == 0:
d = d + 1
print(d)
This tells us the smallest is 18 so and dividing by 19 gives .
So what is ? If we try setting we get a = 52631578947368421, which doesn't work. Next we try which gives and . Now we have a solution, and it is the smallest possible!
Postscript
I wondered how long the brute force search I contemplated at first would have taken. I worked out a rough estimate and with the standard Python I useit would have been ≅ 1000 years. So I'm glad I didn't try it!
Surprisingly there are hyper-optimised versions of Python that are many orders of magnitude faster and if I had deployed one of these on my Silicon M4 (a technically complex endeavour mind you), it seems I could have found the answer in just under 2 days.
When I was growing up I remember the most common pronunciation around me in North Hertfordshire was GARR-ij. But my impression is GARR-ahj is gaining ground and I think I use both pronunciations nowadays.
The OED offers a third British English variant, guh-RAHJ which seems fairly close to the French word garage we borrowed, which is from garer 'to cover, protect'. (This verb survives into modern French but today means 'to park').
The OED stops there, but other sources stick their etymological necks out a bit more. Wiktionary traces a mongrel ancestry through Old Frankish and Old Norse doublets *warjan and *varask respectively, both thought to be from a Proto-Germanic root *warjana- to do with covering, protecting and so on. This in turn is traced to a Proto-Indo-European root *wer- with the same meaning.
If this is true, which seems quite probable, garage has a series of interesting cognates, all sharing some sense of being over something or protecting it. For example
weir, warn, guarantee, garrison, warren, garment, garnish, garret
It's even possible pert is cognate. This is more surprising, but the derivation is thought to be from a prefixed form *ap-wer-yo‑ which would mean uncover or open. This ended up in Middle English as apert, which got shortened to pert and changed its meaning, via the sense of open, to 'saucy' or 'forward'.
A well known puzzle asks what English number word describes its own length and it's not hard to see the answer is four. This is a fixed-point number: if you count hpw many letters in the word and write that as a word you get back to four.
Less obviously it is also a black hole number: if you begin with any number whatsoever and apply this process repeatedly you always end up at four. Always.
For example
two thousand and twenty six --> twenty three --> eleven --> six --> three --> five -- > four
I wondered what happens in other languages. Is there always a fixed-point? If so is it always a black hole. Here's what I found (hope it's all correct, it was a bit triccky making sure I didn;t forget numbers.)
In English four is a fixed point and a black hole.
In Spanish cinco is a fixed point but not a black hole. It drags in nueve and siete, but other numbers get dragged into a 2-cycle, cuatro --> seis and back again.
In French we have a 4-cycle trois --> cinq --> quatre --> six and back again a nd this is an attractor for all other numbers (I think). For example
deux mille seize --> quatorze --> huit --> quatre
Finally, in Italian tre is a fixed point and also a black hole.
We can carry out the same investigation in any language that uses an alphabet (at least 2000 of them) but I think these four give a good feel for the sorts of behaviour that can occur.
The Square Peg Problem asks whether every closed path in the plane, if it doesn't intersect itself, contains the four corners of a square, or to put it differently, has an inscribed square. For example this path does, as we can see

The path can be any shape, and is generally referred to as a 'curve', although it can be wholly or partly made up of straight line segments.
The problem was posed in 1911 by Otto Toeplitz. It is quite intuitive to grasp and feels highly plausible. Yet despite more than a century of chipping away at it, the question is not completely answered. But it has been solved for many special cases, including the case of a convex quadrilateral, which was solved by Clarence M. Hebbert in 1914.
Hebbert's solution was noteworthy not just for being an early contribution but also because he showen that in this case there is always at least one solution, and if there is more than one then there infinitely many. Think of that. You can't have 0, or 2, or 42, or 123456789, or a quadrillion. No, the choice is 1 or ∞.
There is actually a ruler and compasses construction for finding an inscribed square in a convex quadrilateral but it is a little fiddly, so I will try to come up with a shorter version. Here I just want to give a 'Look and see' explanation of why if there are as many as two solutions, there must be infinitely many.
Here is a quadrilateral I have constructed so it has two inscribed squares, PQRS and KLMN

Now if we choose points W, X, Y and Z to divide segments MP, LQ, KR and NS, each in the same ratio, these points will form a new inscribed square, and since we can choose any ratio we please we can find infinitely many such squares, as claimed.
There a special name for this situation, where if there is one solution (or in this example two, but same general idea) there are an infinitude. It is called a porism.
Here's a little mind reading trick. Try answering the following questions as quickly as possible and then scroll down to compare your answers with Chat GPT's.
What is the square root of 9?
Think of a vegetable.
Think of a fruit.
Think of a colour.
Think of a tool.
Scroll down
Chat GPT's answers
3
Carrot
Apple
Blue
Hammer
With the exception of the colour (I was expecting Red) these are the same answers that most people give. Why is this? The usual explanation is that answering quickly and following some intellectual effort to think of these root of 9, most people pick a sort of default representative of the category asked for (the fact that a Carrot is a 'root' vegetable gives it a bit of a start too). The trick, often called the Carrot Trick, is very common (29 million Google hits), and numerous variants exist.
So then I asked Gemini AI and it gave all the expected answers. But unfortunately I made the mistake of sending all the questions as a block, so it was able to locate a Reddit post about the Carrot Trick, and just reproduced the answers it found there. But Hammer was not mentioned in the Reddit discussion, so Gemini must have come up with that independently.
There is an interesting discussion of the trick on BBC Future and there it's suggested that the trich tells us something about how our minds work; under time pressure when asked to pick a vegetable we just pick the one that stands out as the archetypal example.
That can't quite explain why Chat GPT gave most of the same responses though. I suppose must be because it has formed a strong association between 'vegetable' and 'carrot'. So is it working differently here from us? I would argue not.
It looks like there is also a cultural dimension. When I asked the Chinese AI DeepSeek the same questions it answered Broccoli, Mango, and Teal, although it still got Hammer.
In his Natural History Pliny the Elder wrote of Druids venerating oak trees and and climbing them on the sixth day of the moon to harvest mistletoe with a golden sickle *.
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"The druids; or the conversion of the Britons to Christianity". Engraving by S.F. Ravenet, 1752, after F. Hayman.¶
This is a vivid story and part of our stereotype of Druids, but perhaps it is just a myth. However we know the concept of the sacred grove plays a prominent part in the religions of many Indo-European cultures (see the WP article on the topic) and in Greece I once visited a holy well in the woods that felt a bit a distant echo of this tradition.
The connects with trees is also supported by the generally accepted etymology (already prefigured by Pliny). Druid seems to come ultimately from ancient PIE roots *doru-, 'tree'§ and *weyd-, 'see, know', so it would mean something like 'tree-knower'.
The word is found in Latin druides and Greek δρυΐδαι (dryidai), borrowed from Old Celtic. Old English had dry, 'magician', a direct borrowing, but Modern English druid came from Latin via French. Modern Gaelic and Welsh have cognates draoidh (dree) and derwydd (dehrooith), presumably directly from Old Celtic. A rough genealogy of these words in shown in this sketch.

* Fans of Asterix the Gaul will be familiar with these details.
¶ Welcome Foundation ICV No 36622 Licensed under Creative Commons.
§ The first root might instead be a word meaning 'strong' or the two words might be the same (trees are emblematic of strength).
Why is the cloth flannel called flannel?
One theory is that it a borrowing from Welsh gwlanen, 'flannel', which according to the OED is < gwlân, 'wool' (the traditional material for making flannel) and before that < Old Celtic *wlanā.
Wiktionary, on the other hand, suggests it was borrowed into Middle English from Anglo-Norman flanelle, 'wool', ultimately via Gaulish from the same Old Celtic root *wlanā. This in turn would have come from a Proto-Indo-European root *wele-.
Either way a Celtic origin seems quite likely and of course it's possible both these origins, the Welsh and the Anglo-Norman, might have influenced the Middle English word, flaunneol. Here's a quote from c. 1300 I found in the Middle English Compendium
Flaunneol & bursas
This is earlier than the first quotation given in the OED. I believe Bursas refers to traditional fabrics, silk, velvet and the like, from Bursa in Turkey.
The same PIE root is also thought to be the origin of wool, < Old English wull, < Proto Germanic *wullō. There are a host of related words in different Indo-European languages, Two interesting ones are Greek lenos, which I'm guessing was wlenos in Archaic Greek, before Greel lost the /w/ consonant, and the doublet lana 'wool' and vellus 'fleece' in Latin.
A convex polygon is one that has no reentrant corners, or to put it differently, has no interior angles greater than . Figure 1 below is convex; Figure 2 is not.

An acute angle is one that is less than a tight angle, that is, less than .
Prove that a convex polygon with sides can never have more than acute angles and that for any it is possible to construct a polygon with exactly acute angles.
For the proof, see the Comments.
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