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Edited by Valentin Fadeev, Monday, 21 June 2010, 19:59

Strolling struggling on:

equation left hand side open m times z minus n times y close times normal partial differential times z divided by normal partial differential times x plus open n times x minus l times z close times normal partial differential times z divided by normal partial differential times y equals right hand side l times y minus m times x

This is an inhomogeneous equation. Following the theory we try to
find the general solution in an implicit form:

cap v of z comma x comma y equals zero

It is proven that the solution found in this form is indeed
general, i.e. we are not losing any solutions on the way.

equation left hand side normal partial differential times z divided by normal partial differential times x equals right hand side negative normal partial differential times cap v divided by normal partial differential times x divided by normal partial differential times cap v divided by normal partial differential times z

equation left hand side normal partial differential times z divided by normal partial differential times y equals right hand side negative normal partial differential times cap v divided by normal partial differential times y divided by normal partial differential times cap v divided by normal partial differential times z

sum with, 3 , summands open m times z minus n times y close times normal partial differential times cap v divided by normal partial differential times x plus open n times x minus l times z close times normal partial differential times cap v divided by normal partial differential times y plus open l times y minus m times x close times normal partial differential times cap v divided by normal partial differential times z equals zero

Now we can write the associated system (in the symmetrical form):

equation sequence d times x divided by m times z minus n times y equals d times y divided by n times x minus l times z equals d times z divided by l times y minus m times x equals d times t

Or more conveniently for this example, in the canonical form:

equation left hand side d times x divided by d times t equals right hand side m times z minus n times y

equation left hand side d times y divided by d times t equals right hand side n times x minus l times z

equation left hand side d times z divided by d times t equals right hand side l times y minus m times x

Multiplying these equations by l, m and n respectively and summing we get:

d times open sum with, 3 , summands l times x plus m times y plus n times z close divided by d times t equals zero

equation left hand side sum with, 3 , summands l times x plus m times y plus n times z equals right hand side cap c sub one

This is one of the first integrals of the system. Now multiplying the equations by x, y and z respectively amd summing we obtain:

one divided by two times d times open sum with, 3 , summands x squared plus y squared plus z squared close divided by d times t equals zero

equation left hand side sum with, 3 , summands x squared plus y squared plus z squared equals right hand side cap c sub two

Therefore, the general solution has the following form:

normal cap phi of sum with, 3 , summands l times x plus m times y plus n times z comma sum with, 3 , summands x squared plus y squared plus z squared equals zero

Geometrically the first solution represents a plane in a 3d space with angular coefficients of the normal vector cosine of alpha colon cosine of beta colon cosine of gamma equals l colon m colon n . The second integral represents a sphere centered at the origin. Therefore, the characteristics of the equation (the curves,

resulting from intersection of these surfaces) are the circles centered on the line passing through the origin with the above mentioned angular coefficients.

Indeed, another way to look at it is rewrite the equation in the following form:

$$\left|\begin{array}{ccc}

\frac{\partial u}{\partial x} & \frac{\partial u}{\partial y} & \frac{\partial u}{\partial z}\\

l & m & n\\

x & y & z\end{array}\right|=0$$

Or:

tau right arrow dot operator open n right arrow multiplication r right arrow close equals zero

Where tau right arrow is a tangential vector to the surface u of x comma y comma z equals zero , n right arrow is the vector of the axis of revolution and r right arrow is the radius vector of an arbitrary point on the surface. It means that for every point on the surface the tangent vector must lie in the plane

passing through the axis of revolution. This is natural, for the surface is ontained by rotating a plane curve against the axis.

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